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1.5=4.9x^2
We move all terms to the left:
1.5-(4.9x^2)=0
We get rid of parentheses
-4.9x^2+1.5=0
a = -4.9; b = 0; c = +1.5;
Δ = b2-4ac
Δ = 02-4·(-4.9)·1.5
Δ = 29.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{29.4}}{2*-4.9}=\frac{0-\sqrt{29.4}}{-9.8} =-\frac{\sqrt{}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{29.4}}{2*-4.9}=\frac{0+\sqrt{29.4}}{-9.8} =\frac{\sqrt{}}{-9.8} $
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